# Line slope calculator 4x+3y=28

**Straight line given by points A[1; 8] and B[4; 4]**

## Calculation:

**Slope-intercept form of line:**y = -1.3333x+9.3333

**Canonical form of the line equation:**4x+3y-28 = 0

**Parametric form of the line equation:**

x = 3t+1

y = -4t+8 ; t ∈ R

**Slope:**m = -1.3333

**Slope angle of line: φ =**-53°7'48″ = -0.9273 rad

**X intercept:**x

_{0}= 7

**Y intercept:**y

_{0}= q = 9.3333

**Distance line from the origin:**d

_{0}= 5.6

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; -4)

**Normal vector: n =**(4; 3)

**Midpoint of the segment AB: M =**[2.5; 6]

**Perpendicular Bisector equation:**3x-4y+16.5 = 0

**Vector OA = (1; 8) ; |OA| = 8.0623**

**Vector OB = (4; 4) ; |OB| = 5.6569**

**Scalar product OA .OB = 36**

**Angle ∠ AOB = 37°52'30″ = 0.661 rad**